Shell script that displays number of line in given file

Script:
if [ $# -eq 0 ]
    then
        echo No arguments
else
    for fname in $*
        do
            if [ -f $fname ]
                then
                    echo $fname is a regular file
                    count="wc -l $fname" #wc = word count
                    echo Number of lines in $fname are
                    echo $($count)
            else
                echo $fname is a directory file
            fi
        done
fi

Output:
 root@root:~/os# sh 2d.sh test1
test1 is a regular file
Number of lines in test1 are
10 test1
root@root:~/os# sh 2d.sh test
test is a directory file

Comments

Post a Comment

Popular posts from this blog

Multi-programming with variable number of tasks(MVT) program in C

Program: #include<stdio.h> int main() { int tm,om,n,i; printf("Enter total memory size,memory for OS and # of processes:\n"); scanf("%d%d%d",&tm,&om,&n); int process[n]; for (i = 0; i < n; ++i) { printf("Enter process %d size :\n",i); scanf("%d",&process[i]); } tm = tm - om; for (i = 0; i < n; ++i) { if(tm >= process[i]){ printf("Allocated memory to process :%d\n",i+1); tm = tm - process[i]; }else{ printf("Process %d is blocked\n",i+1); } } printf("External fragmentation is %d.\n",tm); return 0; } Output: Enter total memory size,memory for OS and # of processes: 50 10 5 Enter process 0 size :6 Enter process 1 size :6 Enter process 2 size :6 Enter process 3 size :6 Enter process 4 size :6 Allocated memory to process :1 Allocated memory to process :2 Allocated memory to process :3 Allocated memory to process :4 Allocated mem...
Read more

Multi-programming with fixed number of tasks(MFT) program in C

Program: #include<stdio.h> int main() { int tm,om,n,i,block_size,internal_frag; printf("Enter total memory size,memory for OS and # of processes:\n"); scanf("%d%d%d",&tm,&om,&n); int process[n]; tm = tm - om; block_size = tm / n; for (i = 0; i < n; ++i) { printf("Enter process %d size :\n",i+1); scanf("%d",&process[i]); if(process[i] <= block_size){ internal_frag = internal_frag + block_size - process[i]; printf("Allocated memory to process :%d\n",i+1); }else{ printf("Process %d is blocked\n",i+1); } } printf("Fragmentation is %d.\n",internal_frag); return 0; } Output: Enter total memory size,memory for OS and # of processes: 50 10 4 Enter process 1 size : Allocated memory to process :1 Enter process 2 size : Allocated memory to process :2 Enter process 3 size : Allocated memory to process :3 Enter process 4  size : Alloca...
Read more

Linked file allocation program in C.

Program : #include<stdio.h> int  main(){ int f[50],i,st,len,op,ind,n; for(i=0;i<50;i++) f[i]=0; printf("Enter how many blocks are already allocated:\n"); scanf("%d",&n); printf("Enter blocks already allocated:\n"); for(i=0;i<n;i++){ scanf("%d",&ind); f[ind]=1; } x: printf("Enter the index of starting block and length:\n"); scanf("%d%d",&st,&len); if(f[st] == 0){ for(i=st;i<(st+len);i++){ if(f[i] == 0){ f[i] = 1; printf("%d --> %d \n",i,f[i]); }else{ printf("Block %d already allocated.\n",i); } } }else printf("%d starting block is already allocated.\n",st); printf("Press 1 to continue.....\n"); scanf("%d",&op); if(op == 1) goto x; return 0; } Output: Enter how many blocks are already allocated: 3 Enter blocks already alloca...
Read more