Implementation of Round-Robin scheduling in C

Program:
#include<stdio.h>
int main(){
int bt[10],st[10],wt[10],tt[10];
int n,i,j,count=0,quantum,w1=0,t1=0,t,sq=0;
float aw=0.0,at=0.0;
printf("Enter Number of processes and time quantum:\n");
scanf("%d%d",&n,&quantum);
for(i=0;i<n;i++){
printf("Enter burst time for process-%d:\n",i+1);
scanf("%d",&bt[i]);
st[i]=bt[i];
}
//
while(true){
for(i=0,count=0;i<n;i++){
t=quantum;
if(st[i]==0){
count++;
continue;
}
if(st[i] > quantum){
st[i] = st[i] - quantum;
}else{
if(st[i] >= 0){
t = st[i];
st[i]=0;
}
}
sq=sq+t;
tt[i]=sq;
}
if(n == count){
break;
}
}
//
for(i=0;i<n;i++){
wt[i] = tt[i] - bt[i];
w1+=wt[i];
t1+=tt[i];
}
aw = (float)w1/n;
at = (float)t1/n;
printf("\nBt\tWt\tTt\n");
for(i=0;i<n;i++){
printf("%d\t%d\t%d\n",bt[i],wt[i],tt[i]);
}
printf("Average waiting time = %f \n",aw);
  printf("Average Turn around time = %f \n",at);
  return 0;
}
Output:
Enter Number of processes and time quantum:
3
2
Enter burst time for process-1:
10
Enter burst time for process-2:
5
Enter burst time for process-3:
8

Bt      Wt      Tt
10      13      23
5       10      15
8       13      21
Average waiting time = 12.000000
Average Turn around time = 19.666666